There are in fact many other names for the material derivative. The first partial derivative on the right-hand side of Eq. For engineers and fluid dynamicists, the farthest we go is usually cylindrical coordinates with rare pop-ups of the spherical problem.

The reason for this is that the unit vectors in cylindrical coordinates change direction when the particle is moving. In Cylindrical Coordinate system, any point is represented using ρ, φ and z.. ρ is the radius of the cylinder passing through P or the radial distance from the z-axis. When I first started searching the web for the Navier-Stokes derivation (in cylindrical coordinates) I was amazed at not to come across any such document.

The material derivative effectively corrects for this confusing effect to give a true rate of change of a quantity.

They include total derivative, convective derivative, substantial derivative, substantive derivative, and still others. Navier-Stokes Derivation in Cylindrical Coordinates - Free download as PDF File (.pdf), Text File (.txt) or read online for free. Derivatives of Cylindrical Unit Vectors. (3) is computed at a fixed position in time, thus the unit vectors do not change in time and theur derivatives are identically zero. The form of the material derivative D/Dt is dependent on the coordinate system. φ is called as the azimuthal angle which is angle made by the half-plane containing the required point with the positive X-axis. Unit Vectors The unit vectors in the cylindrical coordinate system are functions of position. Expressions in Cylindrical Coordinates Velocity: Ve e k=++VV Vrr zθθ Gravity: g =++gg grr zee kθθ Differential Operator: 1 rr zr θ ∂∂θ∂ ∇= + +ee k Gradient: 1 r pp … The Material Derivative in Cylindrical Coordinates This one a little bit more involved than the Cartesian derivation. Even till now I haven’t stumbled across any such detailed derivation of this so important an equation. Cylindrical Coordinates Transforms The forward and reverse coordinate transformations are != x2+y2 "=arctan y,x ( ) z=z x =!cos" y =!sin" z=z where we formally take advantage of the two argument arctan function to eliminate quadrant confusion. First, let us do that for a scalar. Spherical Coordinates. Here, I want to derive the material derivative of the velocity field in spherical coordinates. Spherical coordinates are of course the most intimidating for the untrained eye.